if the velocity of a body increases by three times the previous value, the percentage change in KE is
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The percentage of change is 1500%
Explanation:
Assuming you know the formula for calculating the kinetic energy of a body which is given by K.E= 1/2*m*v^2.(where m is the mass of the body,v is the velocity of the body )
Now according to the problem the velocity is increased 3 times.
So if we assume that the initial velocity of the body to be v m/s then the final velocity is 3v m/s.(as it is three times of the initial speed)
Now the new K.E is calculated by putting 3v as velocity in the equation to get the answer.
Thus Final K.E=1/2*m*(3v)^2=9*initial K.E.
So the final kinetic energy becomes 9 times of its initial kinetic energy.
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Explanation:
Assuming you know the formula for calculating the kinetic energy of a body which is given by K.E= 1/2*m*v^2.(where m is the mass of the body,v is the velocity of the body )
Now according to the problem the velocity is increased 3 times.
So if we assume that the initial velocity of the body to be v m/s then the final velocity is 3v m/s.(as it is three times of the initial speed)
Now the new K.E is calculated by putting 3v as velocity in the equation to get the answer.
Thus Final K.E=1/2*m*(3v)^2=9*initial K.E.
So the final kinetic energy becomes 9 times of its initial kinetic energy.
Pls mark me as brainlist ⭐️
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