if the velocity of a body is doubled and mass is reduced to one fourth of its initial velocity the KE is
(a)doubled(b)fourfold(c)same(d)halved
Answers
Answered by
15
K. E = 1/2 (mv²)
= 1/2(m/4)x(2v)²
= 1/2(mv²)
=K. E. is same
Hence the answer is (C)
= 1/2(m/4)x(2v)²
= 1/2(mv²)
=K. E. is same
Hence the answer is (C)
Answered by
4
Answer:
same
Explanation:
K.E= 1/2mV^2
K.E= 1/2(1/4)(2)^2
K.E= 1/2(1/4)(4)
K.E remains same
correct option is C: same
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