Question

if the velocity of a body is doubled and mass is reduced to one fourth of its initial velocity the KE is
(a)doubled(b)fourfold(c)same(d)halved

Answer 1

K. E = 1/2 (mv²)
= 1/2(m/4)x(2v)²
= 1/2(mv²)
=K. E. is same
Hence the answer is (C)

Answer 2

Answer:

same

Explanation:

K.E= 1/2mV^2

K.E= 1/2(1/4)(2)^2

K.E= 1/2(1/4)(4)

K.E remains same

correct option is C: same