Question

If the velocity of a body is given by (2t+3t^2) m/s then, find its velocity after 2 second?​

Answer 1

Explanation:

Correct option is

C

4m/s

Given,

v=(2t+3)m/s

The average velocity in interval 0≤t

avg

=

∫

0

1

dt

∫

0

1

vdt

v

avg

=

∫

0

1

dt

∫

0

1

(2t+3)dt

v

avg

=

t∣

0

1

t

2

+3t∣

0

1

=

1−0

(1

2

+3×1)−(0−0)

v

avg

=4m/s

The correct option is C.