If the velocity of a bullet
becomes in of it's intial relocity
aftes a
displacement ex' The it will
comes to rest after a further
displacement of yo
3
uln
y-
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Answer:
ANSWER
The distance traveled by the particle in the last 2 seconds = distance traveled by particle in nth second- distance traveled by particle in (n-2)th second
So,
s=
2
1
an
2
−
2
1
a(n−2)
2
s=
2
1
a[n
2
−n
2
+4n−4]
s=
2
a
[4n−4]
s=(2n−2)a=2a(n−1).........(1)
Now,
Velocity, v=acceleration×time
v=a×n
a=
n
v
...........................(2)
Substitute value of 'a' from (2) to (1) we get,
s=
n
2v(n−1)
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