Question

If the velocity of a car increases from 50 m/s to 70 m/s in 10

seconds, what will be the acceleration of the taxi?

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Answer 1

Answer:

60 m/s²

Explanation:

Given,

Initial Velocity (u) = 50 m/s

Final Velocity (v) = 70 m/s

we know,

acceleration = u + v/2

= (50+70)/2

= 120/2

= 60 m/s²

Answer 2

Given:-

• Initial Velocity (u) = 50 m/s

• Final Velocity (v) = 70 m/s

• Time (t) = 10 seconds

To Find:-

• Acceleration (a)

Law used:-

• First equation of motion ⟹ v = u + at

Solution:-

Putting the given values in first equation of motion,

$⟹\: v = u+at$

$⟹\: 70 = 50+a×10$

$⟹\: 70-50 = a×10$

$⟹\: a =\dfrac{20}{10}$

$⟹\: a =2$

Hence, the acceleration of the taxi is 2 m/s².

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More to know:-

Second Equation of Motion:-

• $S = ut + \dfrac{1}{2}at²$

Third Equation of Motion:-

• $v²-u²=2as$

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