If the velocity of a car is increased is by 2 times then its kinetic energy
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K. E=1/2mv^2
If velocity becomes twice v=2.then,
K.E=1/2m(2v)^2
=1/2m4v^2
=2mv^2
Hence K. E is increased by 4 times
If velocity becomes twice v=2.then,
K.E=1/2m(2v)^2
=1/2m4v^2
=2mv^2
Hence K. E is increased by 4 times
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