Physics, asked by Hudhaaz, 7 months ago

If the velocity of a car moving with uniform velocity changes
from 20m/s to 40 m/s in 5 s
(a) What is the acceleration of the car?
(b) What is the displacement by the car during this time
interval?
pls fast ​

Answers

Answered by Harsh8557
7

{\underline{\underline{\sf{\red{{\bigstar}\:\:\:Given:-}}}}}

\tiny\:\:\:\:\bullet\:\:\:\sf\orange{Initial\: velocity \:(u) = 20m/s }\\\tiny\:\:\:\:\bullet\:\:\:\sf\green{Final \ velocity \ (v) = 40m/s}\\\tiny\:\:\:\:\bullet\:\:\:\sf\blue{Time \ (t) = 5s}

{\underline{\underline{\sf{\orange{{\bigstar}\:\:\:ToFind:-}}}}}

\tiny\:\:\:\:\bullet\:\:\:\sf\purple{Acceleration \:of\: the\: car}\\\tiny\:\:\:\:\bullet\:\:\:\sf\red{Displacement \  by \ the \ car \ during \ this \ interval}

{\underline{\underline{\sf{\blue{{\bigstar}\:\:\: Solution:-}}}}}

\dag\:\underline{\mathfrak{\purple{Using\: 1st\: equation \:of \:motion }}}

\red{\underline{\boxed{\sf{v = u + at}}}}

{\underline{\sf{\:\:\:\:Where,\:\:\:}}}

\tiny\:\:\:\:\bullet\:\:\:\sf\orange{v = final \:velocity}\\ \tiny\:\:\:\:\bullet\:\:\:\sf\green{u = initial \:velocity}\\\tiny \:\:\:\:\bullet\:\:\:\sf\blue{a = acceleration\: or \:deceleration}\\\tiny \:\:\:\:\bullet\:\:\:\sf\red{t = time}

\dag\:\underline{\mathfrak{\purple{Substituting \: the \: values}}}

\tiny\qquad\quad\rightarrow\:\:\:\:\sf{ a = \dfrac{v-u}{t}}

\tiny\qquad\quad\rightarrow\:\:\:\:\sf{ a = \dfrac{40-20}{5}}

\tiny\qquad\quad\rightarrow\:\:\:\:\sf{a = \dfrac{20}{5}}

\tiny\qquad\quad\rightarrow\:\:\:\:\sf{ a = 4m/s^{2}}

\dag\:\underline{\mathfrak{\purple{Using\: 2nd\: equation \:of \:motion }}}

{\underline{\sf{\:\:\:\:Where,\:\:\:}}}

\red{\underline{\boxed{\sf{s = ut+\frac{1}{2} at^2}}}}

{\underline{\sf{\:\:\:\:Where,\:\:\:}}}

\tiny\:\:\:\:\bullet\:\:\:\sf\orange{s = displacement}\\ \tiny\:\:\:\:\bullet\:\:\:\sf\green{u = initial \:velocity}\\\tiny \:\:\:\:\bullet\:\:\:\sf\blue{t = times}\\\tiny \:\:\:\:\bullet\:\:\:\sf\red{a = acceleration}

\tiny\qquad\quad\rightarrow\:\:\:\:\sf{ s = 20 \times 5 + \frac{1}{2} \times 4\times (5)^2}

\tiny\qquad\quad\rightarrow\:\:\:\:\sf{s = 150m}

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