Question

if the velocity of a car moving with uniform velocity changes from 25 m/s to 50 m/s in 10 second . a) what is the acceleration of the car .b) what is the displacement by the car during the time interval.​

Answer 1

Answer:

Explanation:

Given,

Final velocity, v = 50 m/s

Initial velocity, u = 25 m/s

Time, t = 10 seconds

To Find,

Acceleration, a

Displacement, s

Formula to be used,

1st equation of motion, i.e v = u + at

3rd equation of moton, v² = u² - 2as

Solution,

At 1st we will find acceleration,

Putting all the values, we get

v = u + at

⇒ 50 = 25 + a × 10

⇒ 50 - 25 = 10a

⇒ 25 = 10a

⇒ 25/10 = a

⇒ a = 2.5 m/s².

Hence, the acceleration is 2.5 m/s².

Now the displacement,

v² = u² - 2as

⇒ (50)² = (25)² - 2 × 2.5 × s

⇒ 2500 = 625 × 5s

⇒ 2500 - 625 = 5s

⇒ 1875 = 5s

⇒ 1875/5 = s

⇒ s = 375 m.

Hence, the displacement is 375 m.

Answer 2

✯ Given Data :

• Velocity of car moving with uniform velocity changes from 25 m/s to 50 m/s in 10 seconds.

✯ To Find :

• Acceleration of car and displacement by car during the time interval.

✯ Solution :

As we know that,

• Final velocity (v) = 50 m/s
• Intial Velocity (v) = 25 m/s
• Time (t) = 10 seconds

According to the questions :

We know the first equation of motion :

➜ v = u + at

Substituting the values :

➝ 50 = 25 + a × 10

➝ 50 – 20 = 10 a

➝ 25 = 10 a

➝ a = 25 /10

➝ a = 2.5

• So, the Acceleration (a) is 2.5 m/s².

We know the second equation of motion :

➜ s = ut + 1/2 at²

Substituting the values :

➝ s = 25 × 10 + ½ × 2.5 × 10 × 10

➝ s = 250 + 2.5 × 5 × 10

➝ s = 250 + 125

➝ s = 375

• So, The displacement of the car during the time interval is 375 meters.

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