if the velocity of a car moving with uniform velocity changes from 25 m/s to 50 m/s in 10 second . a) what is the acceleration of the car .b) what is the displacement by the car during the time interval.
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Given :
Final velocity, v = 50 m/s
Initial velocity, u = 25 m/s
Time, t = 10 seconds
To find :
Acceleration, a &
Displacement, s
According to the question,
➞ v = u + at
Where,
v = Final velocity
u = Initial velocity
a = Acceleration
t = Time
➞ Substituting the values,
➞ 50 = 25 + a × 10
➞ 50 - 25 = 10a
➞ 25 = 10a
➞ 25 ÷ 10 = a
➞ 2.5 = a
So,the acceleration is 2.5 m/s².
➞ s = ut + ½ at²
Where,
a = Acceleration
u = Initial velocity
v = Final velocity
s = Distance/ Displacement
➞ s = 25 × 10 + ½ × 2.5 × 10 × 10
➞ s = 250 + 2.5 × 5 × 10
➞ s = 250 + 125
➞ s = 375
So,the displacement of the car during the time interval is 375 meters.
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