English, asked by ekbariloveubolde, 1 month ago

if the velocity of a car moving with uniform velocity changes from 25 m/s to 50 m/s in 10 second . a) what is the acceleration of the car .b) what is the displacement by the car during the time interval​

Answers

Answered by Anonymous
5

 \sf \pmb{Answer :}

Given :

Final velocity, v = 50 m/s

Initial velocity, u = 25 m/s

Time, t = 10 seconds

To find :

Acceleration, a &

Displacement, s

According to the question,

➞ v = u + at

Where,

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time

➞ Substituting the values,

➞ 50 = 25 + a × 10

➞ 50 - 25 = 10a

➞ 25 = 10a

➞ 25 ÷ 10 = a

➞ 2.5 = a

So,the acceleration is 2.5 m/s².

➞ s = ut + ½ at²

Where,

a = Acceleration

u = Initial velocity

v = Final velocity

s = Distance/ Displacement

➞ s = 25 × 10 + ½ × 2.5 × 10 × 10

➞ s = 250 + 2.5 × 5 × 10

➞ s = 250 + 125

➞ s = 375

So,the displacement of the car during the time interval is 375 meters.

Answered by thodapyaarkarlo
6

Answer:

Given :

Final velocity, v = 50 m/s

Initial velocity, u = 25 m/s

Time, t = 10 seconds

To find :

Acceleration, a &

Displacement, s

According to the question,

➞ v = u + at

Where,

v = Final velocity

u = Initial velocity

a = Acceleration

t = Time

➞ Substituting the values,

➞ 50 = 25 + a × 10

➞ 50 - 25 = 10a

➞ 25 = 10a

➞ 25 ÷ 10 = a

➞ 2.5 = a

So,the acceleration is 2.5 m/s².

➞ s = ut + ½ at²

Where,

a = Acceleration

u = Initial velocity

v = Final velocity

s = Distance/ Displacement

➞ s = 25 × 10 + ½ × 2.5 × 10 × 10

➞ s = 250 + 2.5 × 5 × 10

➞ s = 250 + 125

➞ s = 375

So,the displacement of the car during the time interval is 375 meters.

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