Question

if the velocity of a moving body becomes one-fifth m remaining constant), the kinetic energy of the body is ?
It will increase by 25 times or get decrease 25 times?

Answer 1

K.E = 1/2m$v^{2}$

given velocity becomes 1/5th of original,

so v can be taken as v/5 here

substituting this value in K.E formula

= 1/2m(v/5)^2

= 1/2m X $v^{2$/25

here it is decreased 25 times.

Hope it helped

:)