Question

if the velocity of a partical is 10+2t . then the average acceleration between the partical in 2seconds and 5seconds​

Answer 1

Explanation:

Velocity when t=2s is v 2

=10+2×4=18m/s

Velocity when t=5s is v 5

=10+2×25=60m/s

so change in velocity will be Δv=60−18=42m/s

time taken is Δt=5−2=3s

so the average acceleration will be a= Δv/Δt =(42m/s)/3s =14m/s 2

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