Question

If the velocity of a particle is v = At + Bt², where A and B are constants, then the distance travelled by it between 1s and 2s is :
(a) $\frac{3}{2}A + 4B$
(b) 3A + 7B
(c) $\frac{3}{2}A + \frac{7}{3}B$
(d) $\frac{A}{2} + \frac{B}{3}$

Answer 1

the answer is in the image hope it helps