Question

If the velocity of a particle moving on x-axis is given by  v = 3 t 2 − 12 t + 6 v=3t2-12t+6. At which time is the acceleration of particle zero​

Answer 1

Answer:

Answer

The position of a particle moving along x-axis is given by

x=(−2t

3

+3t

2

+5)m

Velocity, v=

dt

dx

=0

−6t

2

+6t=0. . . . . . .(1)

6t(−t+1)=0

−t+1=0

t=1sec

Acceleration, a=

dt

dv

a=−12t+6

a∣

t=1sec

=−12×1+6

a∣

t=1sec

=−6m/s

2