Question

if the velocity of a train starting from rest become 20m/s in 10 second . what is it's acceleration? calculate the distance traveled by the train within this time interval?

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Answer 1

v=20m/s

u=0m/s

t=10sec

$a = v - u \div t \\ a = 20 - 0 \div 10 \\ a = 2 {m \: per \: sec}^{2} \\ d = v \times t \\ d = 20 \times 10 \\ d = 200m$

Answer 2

Answer:

acceleration = 2 m/s^2

Distance traveled = 100 m

Explanation:

Initial velocity (U) = 0 m/s

Final velocity (V)= 20m/s

Time taken( t) =10sec

acceleration(a) = (v-u)/t =(20-0)/10=20/10=2 ms^-2

Distance traveled (s )= ut + 1/2 at^2

= 0×10 + 1/2×2×100

= 100m