Question

If the velocity of a train starting from rest become 72km/h in 10minute find its acceleration
And calculate the distance travelled by train within this time interval

Answer 1

Answer:

Here, u=0,

v=72km/h

=

60×60

72×1000

=20m/s

t=10,min=600s

Acceleration a=

t

v−u

=

6000

20m/s−0

1/30m/s²

Answer 2

Explanation:

u=0

72 km/h

=  72 × 1000 60 × 60 72×100060×60

t = 10 min

= 600 s

Acceleration a =  v − u t v−ut

=  20 m / s − 0 600 20m/s−0600

=  1 30 130 m/s2

(b) v2 = u2 + 2as (20)2

= 02 +  2 × 1 30 × s 2×130×s 400

=  1 15 × s 115×s s

= 400 x 15

= 6000 m

= 6 km

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