If the velocity of a train starting from rest becomes
72 km/h in 400 s, what is its acceleration?
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Answered by
1
Answer:
a) Here, u=0,
v=72km/h
=
60×60
72×1000
=20m/s
t=10,min=600s
Acceleration a=
t
v−u
=
6000
20m/s−0
=
30
1
ms
2
b) v
2
=u
2
+2as
(20)
2
=0
2
+2×
30
1
×s
400=
15
1
×s
s=400×15
=6000m
=6km
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