. If the velocity of a train which starts from rest is 72 km/h (20 m/s) after 5 minute, find out its acceleration and the distance travelled by the train in this time.?
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Answer:
u=0
t=5 minute
=5×60s
v=72km/h
=20m/s
The acceleration is given as:
a=
t
v−u
=
5×60
20−0
=
15
1
m/s
2
s=ut+
2
1
at
2
=0×5×60+
2
1
×
15
1
×300
2
=3000m
Explanation:
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