Question

If the velocity of a train which starts from rest is 72km/hr after 5 minute, find out its acceleration and the distance travelled by the train is this time.​

Answer 1

Answer:

Explanation:

u=0

t=5 minute

=5×60s

v=72km/h

=20m/s

The acceleration is given as:

a=  

t

v−u

​

 

=  

5×60

20−0

​

 

=  

15

1

​

m/s  

2

 

s=ut+  

2

1

​

at  

2

 

=0×5×60+  

2

1

​

×  

15

1

​

×300  

2

 

=3000m