Question

If the velocity of a train which starts from rest is72km/h after 5min find out the acceleration and the distance travelled by the train in this time

Answer 1

Explanation:

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Answer 2

Answer:

Acceleration is 1/15 m/s¯²

Distance is 9000m

Explanation:

$a = \frac{v - u}{t}$

Given,

u = 0m/s

v = 72 km/h = 20m/s

t = 5min = 300sec

$a = \frac{20 - 0}{300}$

$a = \frac{20}{300}$

$a = \frac{1}{15} {meter \: per \: second \: }^{2}$

$s = ut + \frac{1}{2} a {t}^{2}$

$s \: = \frac{1}{2} \times \frac{1}{5} ({300}^{2})$

$s = \frac{1}{10} \times 90000 = 9000$