Question

If the velocity of a wave is 360 m/s and frequency 500 hz then find the path difference corresponding to 60

Answer 1

Solution:

Given,

The path difference corresponding = angle = 60°

Velocity of light, u = 360 m/s

Frequency of the wave, v = 500 Hz

So,

Wavelength of wave = u / v = 360 / 500 = 0.72 m

Distance between two points,

∆x = Wavelength / 2π × 60°

Therefore, ∆x = 0.72/2π × π/3 = 0.12 m

Thus, the path difference corresponding to 60° is 0.12 m.