Question

if the velocity of car moving changes from 25m/s. to 45 m/s in 10 second calculated the acceleration​

Answer 1

Answer:

a=v-u÷t

45-25÷10

15÷10=3/5

Answer 2

Required Solution:

${\underline {\boxed {\Large {\sf \pink { Acceleration = 2m/{s}^{2} } }}}}$

Given:

• Initial velocity of car (u) = 25 m/s
• Final velocity of car (v) = 45 m/s
• Time taken (t) = 10s

To calculate:

• Acceleration (a)

Calculation:

By using the first equation of motion:

• ${\underline {\boxed {\large {\sf { v = u +at } }}}}$

Where,

• v is final velocity
• u is initial velocity
• a is acceleration
• t is time taken

$\sf {⇢ v = u +at}$

$\sf {⇢ 45 = 25 + a \times 10 }$

$\sf {⇢ 45 = 25 + 10a}$

$\sf {⇢ 10a = 45-25}$

$\sf {⇢ 10a = 20}$

$\sf {⇢ a = \dfrac{20}{10} }$

$\sf \blue {⇢ a = 2 }$

Therefore, acceleration of the car is 2m/s^2.

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More information!

Equations of motion:

• v = u + at
• s = ut + ½at²
• v² – u² = 2as

Where,

★ v = final velocity = m/s

★ u = initial velocity = m/s

★ a = acceleration = m/s²

★ s = distance/displacement = m

★ t = time = sec

Remember that!

• When a body starts from rest, its initial velocity is 0.
• When a body comes to stop or applies breaks, its final velocity is 0.

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