Question

If the velocity of electron in Bohrs first orbit is 4.38 x10 raised to power 6 m/s.what is deBrogle wavelength associated with it.
100pm
166pm
367pm
56pm

Answer 1

Answer:

डेरा डालने से आप क्या समझते हैं? स्पष्ट कीजिए।

Explanation:

Answer 2

Answer:

According to de Broglie's equation

λ=

mv

h

where, λ= de-Broglie wavelength

h=6.626×10

−34

Js=Planck's constant

m=mass of electron=9.1×10

−31

kg

velocity of electron, v=2.19×10

6

m/s

upon substitution we get:

λ=

9.1×10

−31

×2.19×10

6

6.626×10

−34

λ=0.332×10

−9

=3.32×10

−10

m