Question

If the velocity of light acceleration due to gravity pressure

Answer 1

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Units of...

c = m/s

g = m/s^2

P = (kgm/s^2) / m^2 = kg / (ms^2)

Dimensional formula of...

c = [LT^-1]

g = [LT^-2]

P = [ML^-1 T^-2]

c^a g^b P^c = [L] = [LT^-1]^a [LT^-2]^b [ML^-1 T^-2]^c

[L] = [L]^(a + b - c) [T]^(-a - 2b - 2c) [M]^c

From above equation

1 = a + b - c ——(1)

0 = -a - 2b - 2c —-(2)

0 = c ——(3)

Substitute c = 0 in equation (1) and (2)

1 = a + b ; a = -2b

From above equations

b = -1 and a = 2

Finally we got

a = 2

b = -1

c = 0

The dimension of length is therefore

c^a g^b P^c = c^2 g^-1 P^0 = (c^2) / g

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