Question

If the velocity of projection of a body is increased by 1 percent, other things remaining constant, the horizontal range will increase by (1) 1% (2)2% (3) 4% (4) 8%​

Answer 1

Answer:

hey i guess u asked this question many times

Explanation:

easy

horizontal range=v^2sin2x/g

now case--1

v=y

horizontal range=y^2sin2x/g

case---2

increased by1 %

y+y/100=101y/100 is new v

1.01y=new v

horizontal range=(1.01y)^2sin2x/g=1.02y^2 sin2x/g

change in answer is  jus 0.02y leave sin2x and g they are constant and will be cancelled

now change in answer==0.02y^2

% change=change in answer/original answer*100=0.02/1*100=2%

Answer 2

Answer:

=> Option (2) - 2%

Explanation

=> If the velocity of projection of a body is increased by 1 percent, other things remaining constant, the horizontal range will increase by 2%.

Thanks!!☺️☺️☺️