If the velocity of the car of mass 1500kg is increased from 30km/hr to 60km/hr, the work done will be (in KJ)?
Answers
Answered by
0
KE = Work done
=1/2 mv^2
1 x 15000 x (60 - 30)^2/2
=6750000 J =6750 KJ
=1/2 mv^2
1 x 15000 x (60 - 30)^2/2
=6750000 J =6750 KJ
Adityaadidangi:
bro speed is in km/hr firstly convert it n m/s
yes i need to change
I am unable to delete that ans. else i would have
leave it
Answered by
2
work done = change in kinetic energy
=1/2m(v₁²-v₂²)
=1/2×1500((60×5÷18)^2-(30×5÷18)^2)
=156250J
=156.25KJ
=1/2m(v₁²-v₂²)
=1/2×1500((60×5÷18)^2-(30×5÷18)^2)
=156250J
=156.25KJ
Similar questions