Question

If the velocity of the electron in bohr's 1st orbit is 2.19*10^-6m/s.calculate the wave length associated with it by de broglie equation

Answer 1

Explanation:

ANSWER

According to de Broglie's equation

λ=

mv

h

where, λ= de-Broglie wavelength

h=6.626×10

−34

Js=Planck's constant

m=mass of electron=9.1×10

−31

kg

velocity of electron, v=2.19×10

6

m/s

upon substitution we get:

λ=

9.1×10

−31

×2.19×10

6

6.626×10

−34

λ=0.332×10

−9

=3.32×10

−10

m