Question

If the velocity of the electron in Bohr's first orbit is 2.19 x 10^6 ms-1. calculate the de debroglie wavelength
associated with it.


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Answer 1

Answer:

According to de Broglie's equation 

λ=mvh

where, λ= de-Broglie wavelength

h=6.626×10−34Js=Planck's constant

m=mass of electron=9.1×10−31 kg

velocity of electron, v=2.19×106 m/s

upon substitution we get:

λ=9.1×10−31×2.19×1066.626×10−34

λ=0.332×10−9=3.32×10−10m

Explanation:

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