If the velocity of the electron in electron microscope is measured as 1.6x10m/s,
calculate de Broglie wavelength in pm associated with this electron.
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Answer:
From de Broglie’s equation,
λ = h/mv
Substituting the values in this equation,we get
6.626x 10-34 / (9.11x10-31)(1.6x106)
= 4.55 x 10-10m
= 455pm
Explanation:
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