Question

If the velocity of the electron in first orbit of H atom is 2.18×10^6m/s, what is its value in third orbit?

Answer 1

we have formula to calculate the velocity of electron .

Ve=Vo*Z/n.

Answer 2

Answer: The value of the velocity of an electron in third orbit will be $0.72\times 10^6 m/s$.

Explanation:

Generally the velocity of the electron in nth orbit is given by :

$v_n=\frac{2\pi^2Kme^Z}{n}=(2.165\times 10^{6})\frac{Z}{n} m/s$

$v_1=2.165\times 10^{6} m/s$

Since, it is given that the velocity of the electron in first orbit of H atom = $2.18\times 10^6m/s$, Z= 1, n= 3

So, $v_3=(2.18\times 10^6)\frac{Z}{n}=(2.18\times 10^6)\frac{1}{3}=0.72\times 10^6 m/s$

The value of the velocity of an electron in third orbit will be $0.72\times 10^6 m/s$.