Question

if the velocity of the electron is 1.6×106ms-1 calculate de brogile wavelength associated with the electron.l
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Answer 1

Answer:

455 pm

Explanation:

wait for the solution.

λ=

mv

h

=

9.11×10

−31

×1.6×10

6

6.626×10

−34

=4.55×10

−10

m=455 pm

Answer 2

Answer:

Explanation:

We have,

 λ=h/mv

   =6.6*10^-34 / (9.1*10^ -31* 1.6*10^6 )

   =4.5*10^-15 m