If the velocity of the object is increased by 0.1%, then the kinetic energy is increased by *
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Old K.E. = ½mv²
When v = v + 0.1%v
» v' = v + v/1000
» v' = 1001v/1000
New K.E. = ½m(1001v/1000)²
Percentage increase = [½m.1001v²/1000² - ½mv²]/½mv² × 100
» 2.001%
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0
Answer:
0.2% is age change in kinetic energy.
Explanation:
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