if the velocity of the object is increased by 0.1 %, then the kinetic energy is increased by:
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Answer:
old K.E.=½mv²
Explanation:
when v = v + 0.1%v
v = v + v/1000
v = 1001v/1000
New K.E. = ½m( 1001v/1000)²
Percentage increase = (½m.1001v²/1000² - ½mv² × 100
= 2.001%
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