Question

If the velocity of the particle in circular motion is given by omaga is equal to 2t square plus 2 ​

Answer 1

$\huge \mathfrak \red{hey \: mate}$

The position vector of an object moving in a plane is given by r(t)=3t4i + 6t2j. Find its ... Let's first calculate the velocity then the acceleration: ... a(t) = v'(t) = s''(t) = –80sin(4t ...

$\red{hope \: this \: helps}$