Question

if the velocity of train which start from restis 72km/h(20m/s) after 5 min. find out the acceleeationand the distance travel by the train on this time​

Answer 1

Answer:

v=u+at

a=(v-u)/t -----------(1)

v=72 km/h

=20m/s

u=0

t=5*60 sec =300sec

by putting values of v,u,t in (1)

a=1/15 m/s2

s=ut +(1/2)at2

=0+(1/2)(1/15)(300)(300)

=3km

Answer 2

At first use ...1st equ of motion do u will get Acc. After that by 3rd equation of motion u will get distance .