Question

if the velocity(v),acceleration(a) and force(f) are taken as fundamental quantities instead of mass(m),length(l),time(t) the dimension of youngs modulus(Y) is

Answer 1

dimensional formula of young's modulus is ML-1T-2
Well it is write answer I am sure
I hope it helps u

Answer 2

Answer:

v^−4Fa^2

Explanation:

Young's Modulus (Y)=Stress/Strain=F/A/l/L

F is a fundamental quantity. Dimension of length in new fundamental units,

L=v2a

Therefore, A has a dimension,

A=v^4/a^2

Strain is dimensionless.  

Dimension of Young's Modulus,

Y=F/v^4/a2=v^−4Fa^2