Question

if the velocity v of a body in time t is given by v=At3+bt3+ct+D then the dimensions of C are​

Answer 1

Answer:

LT^(-2)

Explanation:

Velocity's dimensions are LT^(-1) which should be same as ct so dimensions of CT is LT^(-1) giving the dimensions of C as LT^(-2)

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Answer 2

Answer:

[LT⁻²]

Given:

Velocity (v) of a body in time (t) in given by,

v = At³ + Bt³ + Ct + D

Find:

The dimensions of C.

Explanation:

According to the principle of homogeneity (It states that every equation relating physical quantities must be dimensionally homogeneous.), we have,

Dimensions of v = Dimensions of At³ + Bt³ + Ct + D

Or we can say that,

Dimensions of v = Dimensions of Ct

Dimensions of v/Dimensions of t = Dimensions of C

Dimensions of C = [LT⁻¹]/[T]

Dimensions of C = [LT⁻¹⁻¹]

                            =  [LT⁻²]

Hence, the dimensions of C are [LT⁻²].

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