Question

If the velocity v of a particle moving along a straight line decreases linearly with its displacement from 20m/s to a value approaching zero at s=30m, determine the acceleration of the particle when s=15m.

Answer 1

Answer:

Initial velocity(u)=20m/s

Final velocity (v)=0m/s

Displacement (s)=30m

Let the acceleration be a

${v}^{2} - {u }^{2} = 2as$

0^2 - 20^2= 2×(-a)×30

20×20=2×a×30

a=20/3m/s^2

Since the velocity decreases linearly with it's displacement so the acceleration remains constant throughout its motion

So the acceleration at s=15 m is a retarding acceleration of 20/3 m/s^2

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