If the vertex angle of an isosceles triangle is 100⁰, then the measure of an exterior angle to one of the base angles of this triangle is
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(d) 130°
The exterior angle is always equal to sum of two opposite interior angles .
The other two angles will be (180-80)/2 each that is 50° each .
Now, vertex angle + base angle = 80° + 50° = 130°
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