Question

If the vertex angle of an isosceles triangle is 80° then the measure of an exterior angle to one of the base angle of this triangles is ​

Answer 1

Answer:

∠A + ∠ B + ∠C = 180°

∠ B = ∠C (isosceles triangle)

⇒ ∠ B + ∠C = 180 - 80 = 100°

⇒  ∠B = ∠C = 50°

⇒ their exterior angle = 180 -50 = 130°

Answer 2

Step-by-step explanation:

130° is the answer.......