If the vertical angle of an isosceles triangle is100 degree then find the measures of its base angles
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No Bhai 100 degree nahi ho ga
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Bhai wahi hai
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Base angle of a triangle are equal ,so (angle A) =(angle b)
Sum of all angle of a triangle is =180°
so angle A°+ angle B°+ angle C°=180°
A°+B°+100=180°
Let angle A and B =x
x + x =180°-100°
2x=80°
x =80°/2 =40°
so ,angle A and angle b =40°
If you are intelligent you can understand how this question is solved
Sum of all angle of a triangle is =180°
so angle A°+ angle B°+ angle C°=180°
A°+B°+100=180°
Let angle A and B =x
x + x =180°-100°
2x=80°
x =80°/2 =40°
so ,angle A and angle b =40°
If you are intelligent you can understand how this question is solved
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