Question

if the vertices of a triangle are (1,1) (-2, 7) and (3,-3) then its area is​

Answer 1

Answer:

$\tt {\pink{Given:}}$

Coordinates 1 (x₁, y₁) = (1, 1)

Coordinates 2 (x₂, y₂) = (-2, 7)

Coordinates 3 (x₃, y₃) = (3, -3)

$\tt {\pink{Formula:}}$

$Area =\frac{1}{2} [x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)]$

$Area =\frac{1}{2} [1(7 + -3) - 2(-3 - 1) + 3(1 - 7)]\\\\=\frac{1}{2} [1(10) - 2(-4) + 3(-6)]\\\\=\frac{1}{2} (10 + 8 - 18)\\\\=\frac{1}{2} (0)\\\\Area = 0 units^2$

THUS THE LINES ARE COLLINEAR BECAUSE AREA = 0.

HOPE THIS HELPS :D