Question

If the vertices of a triangle are (1,-3), (4, p) and (-9, 7) and its area is 15sq.units, find
the values of p.

Answer 1

Answer:

fhiohgfyyhb

Step-by-step explanation:

fjiuh

fkoigb

fyjknk

Answer 2

The values of p are -3, -9.

• Given vertices are

              $A(x_{1},y_{1})=(1,-3)$

              $B(x_{2},y_{2})=(4,p)$

              $C(x_{3},y_{3})=(-9,7)$

• Area of triangle = 15 sq units

         $\frac{1}{2}|x_{1}(y_{2}-y_{3})+x_{2}(y_{3}-y_{1})+x_{3}(y_{1}-y_{2})|=15$

         $\frac{1}{2}|1(p-7)+4(7+3)-9(-3-p)|=15$

          |p - 7 + 40 + 27 + 9p| = 30

          10p + 60 = ± 30

        Case(I):

           10p + 60 = 30

            10p = 30 - 60

            10p = -30

             p = - 3

          Case(II):

             10p + 60 = -30

             10p = -60 - 30

             10p = - 90

               p = -9