Math, asked by shahchitra9505, 11 months ago

If the vertices of a triangle are (5,2) (2/3,2) (-4,3) then area of the triangle is

Answers

Answered by India21vns
0

Answer:

13/6

Step-by-step explanation:

hope you know what is deteminant.

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Answered by SocioMetricStar
0

The area of the triangle is \frac{13}{6} square units.

Step-by-step explanation:

The vertices of a triangle are (5,2) (2/3,2) (-4,3)

Thus, we have

x_1=5,y_1=2,x_2=2/3,y_2=2,x_3=-4,y_3=3

Area of a triangle is given by the formula

A=|\frac{1}{2}\left[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)\right]|

Substituting the known values, we get

A=|\frac{1}{2}\left[5(2-3)+\frac{2}{3}(3-2)-4(2-2)\right]|

On simplifying, we get

A=|\frac{1}{2}\cdot\frac{-13}{3}|\\\\A=|\frac{-13}{6}|\\\\A=\frac{13}{6}

The area of the triangle is \frac{13}{6} square units.

#Learn More:

Find the area of the triangle with vertices (0,0),(6,0),(0,5)

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