Question

If the vertices of a triangle are P (1, 3), Q (2, 5) and R(3, − 5), then the centroid of a DPQR is.​

Answer 1

Answer:

(−4,−15)

Let the △ABC has vertices A=(x1,y1)=(−1,4),B=(x2,y2)=(5,2) and C=(x3,y3).

The centroid G=(3x1+x2+x3,3y1+y2+y3)=(0,−3)

Therefore, 3−1+5+x3=0

⇒x3=−4

Also 34+2+y3=−3

⇒y3=−15

∴C=(x3,y3)=(−4,−15)

Answer 2

Answer-:

(−4,−15)

Step-by-step explanation:

Let the △ABC has vertices A=(x1,y1)=(−1,4),B=(x2,y2)=(5,2) and C=(x3,y3).

The centroid G=(3x1+x2+x3,3y1+y2+y3)=(0,−3)

Therefore, 3−1+5+x3=0

⇒x3=−4

Also 34+2+y3=−3

⇒y3=−15

∴C=(x3,y3)=(−4,−15)