if the vertices of triangle ABC are A(0,-6) B(2,5) C(-1,3) and P(x,y) is a point in the interior of triangle ABC ,show that the ratio of area of triangle PBC to triangle ABC is (2x-3y+11)/49
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The ratio of area of triangle Δ PBC to triangle Δ ABC is .
Step-by-step explanation:
The triangle Δ ABC has vertices A(0,-6), B(2,5) and C(-1,3) and P(x,y) is a point in the interior of the triangle Δ ABC.
Now, the area of the Δ ABC = sq. units.
And the area of the Δ PBC = sq. units.
Therefore, the ratio of the area of triangle Δ PBC to triangle Δ ABC is (Answer)
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