Question

If the vertices of triangle ABC are A(5,-1) B (-3,-2) C(-1,8) Find the length of median through A​

Answer 1

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Answer 2

≛ Question :-

If the vertices of triangle ABC are A(5,-1) B (-3,-2) C(-1,8) Find the length of median through A.

≛ Given that :-

A ΔABC, and the vertices of the triangle A(5,-1) B (-3,-2) C(-1,8).

Let AD be the median through A, such that BD = DC (as D is the mid point of BC)

(for more explaination refer the attachment)

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$Coordinates \: of \: D \: will \: be = ( \frac{ - 3 - 1}{2} ),( \frac{ - 2 + 8}{2} )$

$Coordinates \: of \: D \: will \: be = ( \frac{ - 4}{2} ),( \frac{ 6}{2} )$

$Coordinates \: of \: D \: will \: be = ( - 2,3)$

Now, Length of the median AD

= √[{5-(-2)}^2 + {-1-3}^2]

= √{7^2 +(-4)^2}

= √(49+16)

= √65 ans.

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