If the vertices of triangle are (2, 0) (11, 6) and (–4, –4) then the area is
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0
Answer:
Area of triangle having vertices (x
1
,y
1
),(x
2
,y
2
) and (x
3
,y
3
) is given by
Area =
2
1
×[x
1
(y
2
−y
3
)+x
2
(y
3
−y
1
)+x
3
(y
1
−y
2
)]
Therefore, area of required triangle is given by
=−11−2+38
=
2
1
25
=
2
25
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Answer:
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