Question

if the vertices of triangle are(3,1),(4,2),(5,3) find area of triangle?

Answer 1

Answer:

The area of the triangle is 0, and hence the points are collinear

Step-by-step explanation:

Given vertices of the triangle are (3, 1), (4, 2), (5, 3)

Let (x1, y1) = (3, 1), (x2, y2) = (4, 2), (x3, y3) = (5, 3)

We know that area of the triangle whose vertices are (x1, y1), (x2, y2), (x3, y3) is

$\frac{1}{2}|x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|$

Area of triangle

= 0.5 | 3(2 - 3) + 4(3 - 1) + 5(1 - 2) |

= 0.5 | -3 + 8 - 5|

= 0.5 (0)

= 0

Area of triangle = 0

Given vertices (3, 1), (4, 2), (5, 3) are collinear since the area of the triangle is 0