Question

If the voltage applied across a device is
4V and a charge of 12 C is flowing in 6
sec through the device then the power
dissipated as heat is
A. 18 watt
B. 2 watt
b. 8 watt
D.. None of these
I​

Answer 1

8watt

Explanation:

i=q/t

Q=12C

T=6sec

THEREFORE

12/6=2A

power=voltage*current

power= 4volt*2A

power=8watt